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軟件設(shè)計師每日一練試題內(nèi)容(2022/10/16)
試題1
()不屬于按尋址方式劃分的一類存儲器。
A.隨機存儲器
B.順序存儲器
C.相聯(lián)存儲器
D.直接存儲器
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試題參考答案:C
試題2
某n階的三對角矩陣A如下圖所示,按行將元素存儲在一維數(shù)組M中,設(shè)a1,1存儲在M[l],那么ai,j(l<=i,j<=n且ai,j位于三條對角線中)存儲在M( )。查看答案
試題參考答案:D
試題3
在進行金融業(yè)務(wù)系統(tǒng)的網(wǎng)絡(luò)設(shè)計時,應(yīng)該優(yōu)先考慮(1)原則。在進行企業(yè)網(wǎng)絡(luò)的需求分析時,應(yīng)該首先進行(2) 。
(1)A、先進性
B、開放性
C、經(jīng)濟性
D、高可用性
(2)A、企業(yè)應(yīng)用分析
B、網(wǎng)絡(luò)流量分析
C、外部通信環(huán)境調(diào)研
D、數(shù)據(jù)流向圖分析
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試題參考答案:D、A
試題4
分配給某校園網(wǎng)的地址塊是202.105.192.0/18,該校園網(wǎng)包含 ( ) 個C類網(wǎng)絡(luò)。
A、6
B、14
C、30
D、62
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試題參考答案:D
試題5
進行面向?qū)ο笙到y(tǒng)設(shè)計時,針對包中的所有類對于同-類性質(zhì)的變化;一個變化若對一個包產(chǎn)生影響,則將對該包中的所有類產(chǎn)生影響,而對于其他的包不造成任何影響。這屬于( )設(shè)計原則。查看答案
試題參考答案:D
試題6
計算機指令一般包括操作碼和地址碼兩部分,為分析執(zhí)行一條指令,其 ( ) 。
A、操作碼應(yīng)存入指令寄存器(IR),地址碼應(yīng)存入程序計數(shù)器(PC)
B、操作碼應(yīng)存入程序計數(shù)器(PC),地址碼應(yīng)存入指令寄存器(IR)
C、操作碼和地址碼都應(yīng)存入指令寄存器(IR)
D、操作碼和地址碼都應(yīng)存入程序計數(shù)器(PC)
查看答案
試題參考答案:C
試題7
Software entities are more complex for their size than perhaps any other humanconstruct, because no two parts are alike (at least above the statement level). If they are, wemake the two similar parts into one, a( 71 ), open or closeD. In this respect software systemsdiffer profoundly from computers, buildings, or automobiles, where repeated elements abound.
Digital computers . are themselves more complex than most things people build;they have very large numbers of states This makes conceiving, describing, and testing them harD. Software systems have orders of magnitude more( 72 )than computers do
Likewise, a scaling-up of a software entity is not m erely a repetition of the same elementsm larger size; it is necessarily an mcrease in the number of different elements. In most cases, the elements interact with each other in some( 73 )fashion: and the complexity of the wholencreases much more than linearly.
The complexity of software is a(an)( 74 )property, not an accidental one Hencedescriptions of a software entity that abstract away its complexity often abstract away its essence.Mathematics and the physical sciences made great strides for threecenturies by constructingsimplified models of complex phenomena, deriving properties fiom the models, and verifyingthose properties experimentally. This worked becausethe complexities( 75 ) in the modelswere not the .essential properties of the phenomena: It does not work when the complexities are the essence.
Many of the classical problems of developing software products derive from this essential complexi and its nonlinear uicreases with size. Not only .technical problems but management problems as well come from the coin plexity.
A. task
B.job
C.subroitune
D.Program
A.states
B.parts
C.conditions
D.Expressions
A.linear
B. nonlinear
C.Parallel
D.Addititive
A. surface
B. Outside
C.exterior
D.Essential
A. fixed
B. Included
C.ignored
D.stabilized
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試題參考答案:C、A、B、D、C
試題8
下圖為一確定有限自動機(DFA)的狀態(tài)轉(zhuǎn)換圖,與該自動機等價的正規(guī)表達式是(1),圖中的(2)是可以合并的狀態(tài)?
(1)A、(a|b)*bb(a*b*)*
B、(a|b)*bba*|b*
C、(a*b*)bb(a|b)*
D、(a|b)*bb(a*|b*)*
(2)A、0和1
B、2和3
C、1和2
D、0和3
查看答案
試題參考答案:A、B
試題9
軟件能力成熟度模型(CMM)的第 4 級(已管理級)的核心是( )
A、建立基本的項目管理和實踐來跟蹤項目費用、進度和功能特性
B、組織具有標(biāo)準(zhǔn)軟件過程
C、對軟件過程和產(chǎn)品都有定量的理解和控制
D、先進的新思想和新技術(shù)促進過程不斷改進
查看答案
試題參考答案:C
試題10
下面關(guān)于校驗方法的敘述, ( ) 是正確的。
A、采用奇偶校驗可檢測數(shù)據(jù)傳輸過程中出現(xiàn)一位數(shù)據(jù)錯誤的位置并加以糾正
B、采用海明校驗可檢測數(shù)據(jù)傳輸過程中出現(xiàn)一位數(shù)據(jù)錯誤的位置并加以糾正
C、采用海明校驗,校驗碼的長度和位置可隨機設(shè)定
D、采用 CRC 校驗,需要將校驗碼分散開并插入數(shù)據(jù)的指定位置中
查看答案
試題參考答案:B
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