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網(wǎng)絡(luò)工程師每日一練試題內(nèi)容(2022/8/25)
試題1
在BGP4協(xié)議中,路由器通過(guò)發(fā)送( 1 )報(bào)文將正常工作信息告知鄰居。當(dāng)出現(xiàn)路由信息的新增或刪除時(shí),采用( 2 )報(bào)文告知對(duì)方。查看答案
試題參考答案:C、B
試題2
Traditional IP packet forwarding analyzes the ( 1)IP address contained in then network layee header of each packet as the packet rravels from its sourse to its final destination. A router analyzes the destination IP address independently at each hop in the network. Dynamic ( 2) protocols or staitic configuration builds the database needed to analyze the destination IP address(the routing table). The process of implementing traditional IP routing also is called hop-by-hop destination-based ( 3)routing. Although successful,and obviously widely deployed,certain restrictions,which have been realized for some time,exist for this method of packet forwarding that diminish its ( 4).New techniques are therefore required to address and expand the functionality of an IP-based network infrastructure. This first chapter concertrates on idenfifying these restrictions.and presents a new architecture,known as multiprotocol( 5)switching,that provides solutions to some of this restrictions. ( 1).A.datagram
B.destination
C.connection
D.service
( 2).A.routing
B.forwarding
C.transmission
D.managerment
( 3).A.anycast
B.multicast
C.broadcast
D.unicast
( 4).A.reliability
B.flexibility
C.stability
D.capability
( 5).A.cost
B.cast
C.mark
D.label
查看答案
試題參考答案:B、A、D、B、D
試題3
下面4個(gè)主機(jī)地址中屬于網(wǎng)絡(luò)110.17.200.0/21的地址是(53) 。
A. 110.17.198.0
B. 110.17.206.0
C. 110.17.217.0
D. 110.17.224.0
查看答案
試題參考答案:B
試題4
WWW系統(tǒng)采用的傳輸協(xié)議是(?。?br />A.DHCP查看答案
試題參考答案:C
試題5
設(shè)有下面4條路由:196.34.129.0/24、196.34.130.0/24、196.34.132.0/24和196.34.133.0/24,如果進(jìn)行路由匯聚,能覆蓋這4條路由的地址是( )查看答案
試題參考答案:A
試題6
參加下面的網(wǎng)絡(luò)連接圖,4個(gè)選項(xiàng)是Host A的ARP表,如果HostA ping HostB,則ARP表中的哪一選項(xiàng)用來(lái)封裝傳輸?shù)膸浚ǎ?br />
A. A
B. B
C. C
D. D
查看答案
試題參考答案:D
試題7
假設(shè)某公司有8000臺(tái)主機(jī),采用CIDR方法進(jìn)行劃分,則至少給它分配(1)個(gè)C類(lèi)網(wǎng)絡(luò)。如果192.168.210.181是其中一臺(tái)主機(jī)地址,則其網(wǎng)絡(luò)地址為(2)。查看答案
試題參考答案:D、A
試題8
The TCP protocolis a (1) layer protocol. Each connection connects two TCPs that may be just one physical network apart or located on opposite sides ofthe globe. In other words, each connection creates a (2) witha length that may be totally different from another path created by another connection. This means that TCP cannot use the same retransmission time for all connections. Selecting afixed retransnussion time for all connections can result in serious consequences. Ifthe retransmission time does not allow enough time for a (3) to reach the destination and an acknowledgment to reach the source, it can result in retransmission of segments that are still on the way. Conversely, if the retransnussion time is longer than necessary for a short path, it may result in delay for the application programs.Even for one single connection, the retransmission time should not be fixed.A connection may be able to send segments and receive (4)faster during nontraffic period than during congested periods. TCP uses the dynamic retransmission time,a transmission time is different for each connection and which may be changed during the same connection. Retransmission time can be made(5) by basing it on the round-trip time (RTT). Several formulas are used for this purpose.
(1)A、physical
B、network
C、transport
D、application
(2)A、path
B、window
C、response
D、process
(3)A、process
B、segment
C、program
D、user
(4)A、connections
B、requests
C、acknowledgments
D、datagrams
(5)A、long
B、short
C、fixed
D、dynamic
查看答案
試題參考答案:C、A、B、C、D
試題9
在()校驗(yàn)方法中,采用模2運(yùn)算來(lái)構(gòu)造校驗(yàn)位。查看答案
試題參考答案:D
試題10
Blowfish加密算法的分組長(zhǎng)度是( )。查看答案
試題參考答案:A
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